# Line slope calculator 2x+9y=18

**Straight line given by points A[0; 2] and B[9; 0]**

## Calculation:

**Slope-intercept form of line:**y = -0.2222x+2

**Canonical form of the line equation:**2x+9y-18 = 0

**Parametric form of the line equation:**

x = 9t

y = -2t+2 ; t ∈ R

**Slope:**m = -0.2222

**Slope angle of line: φ =**-12°31'44″ = -0.2187 rad

**X intercept:**x

_{0}= 9

**Y intercept:**y

_{0}= q = 2

**Distance line from the origin:**d

_{0}= 1.9524

**The length of the segment AB: |AB| =**9.2195

**Vector: AB =**(9; -2)

**Normal vector: n =**(2; 9)

**Midpoint of the segment AB: M =**[4.5; 1]

**Perpendicular Bisector equation:**9x-2y-38.5 = 0

**Vector OA = (0; 2) ; |OA| = 2**

**Vector OB = (9; 0) ; |OB| = 9**

**Scalar product OA .OB = 0**

**Angle ∠ AOB = 90° = 1.5708 rad**